# On your graph what is the pressure of the gas when the volume is 30.0 ml

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[Note that the correction to P is not significant as T is well above the temperature at which helium gas will liquefy while the volume correction is significant due to the high pressure.] (ii) Using the Ideal Gas Equation: Substituting in PV = nRT, 120 x 10.0 = 20.0 x 0.0821 x T T = 1200/1.642 = 731 K
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Indicate whether the final volume of gas in each of the following is the same, larger, or smaller than the initial volume, if pressure and amount of gas do not change. a. b c. A volume of 505 mL of air on a cold winter day at -150C is breathed into the lungs, where body temperature is 370C.
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RESULTS & QUESTIONS A. Boyle's Law Table 1 Reading Pressure (P) Volume (V) P V (Product) 1 630 mm Hg 32.0 mL 20160.0 2 690 mm Hg 29.2 mL 20148.0 3 726 mm Hg 27.8 mL 20182.8 4 790 mm Hg 25.6 mL 20224.0 5 843 mm Hg 24.0 mL 20232.0 6 914 mm Hg 22.2 mL 20290.8 1.
The sample of gas in Figure 5 has a volume of 30.0 mL at a pressure of 6.5 psi. Determine the volume of the gas at a pressure of 11.0 psi, using: (a) the P–V graph in Figure 5 (b) the $\frac{1}{P}$ vs. V graph in Figure 5 (c) the Boyle’s law equation. Comment on the likely accuracy of each method. [Note that the correction to P is not significant as T is well above the temperature at which helium gas will liquefy while the volume correction is significant due to the high pressure.] (ii) Using the Ideal Gas Equation: Substituting in PV = nRT, 120 x 10.0 = 20.0 x 0.0821 x T T = 1200/1.642 = 731 K
The sample of gas has a volume of 30.0 mL at a pressure of 6.5 psi. Determine the volume of the gas at a pressure of 11.0 psi, using: the P-V graph in Figure $$\PageIndex{6a}$$ the $$\dfrac{1}{P}$$ vs. V graph in Figure $$\PageIndex{6b}$$ the Boyle's law equation; Comment on the likely accuracy of each method. Answer a . about 17-18 mL ...30.0 cm3 of a dry gas at 14 'C to 22 cm3 16.4 ml. of a dry gas at 28 to 20.0 ml. 39 cm3 of a dry gas at 0.0 'C to 35 30.0 ml. of a dry gas at 5 'C and 760 mmHg to 55 rnL and 780 mmHg 1.0 L of a dry gas at 10.0 and 106.6 kpa to 0.50 L and 101.3 kPa 10.0 cm3 of a dry gas at 20.0 'C and 101.3 kPa to 1.0 crn3 and 106.6 kPa Group IV. Example - Volume Change when Air is Heated. 2 m 3 of air is heated from 22 o C to 43 o C.The volume correction factor is 1.08 and the new volume can be calculated as (2 m 3) 1.08 = 2.16 m 3
Q2 On your graph, what is the volume of the gas at a pressure of 760 mmHg? Q3 On your graph, what is the pressure of the gas when the volume is 30.0 mL? 04 A sample of helium has a volume of 325 mL and a pressure of 655 mmHg. What will be the pressure, in mmHg, if the sample of helium is compressed to ! (1, n constant)? (Show calculations.) Q5 ...Standard pressure is 1 atmosphere, i.e., 760 mm Hg. Experimentally, one mole of any gas occupies a volume of 22.4 litres at STP. The equation can be expressed as. 1 mole of gas at STP = 22.4 litres of gas. Example 1. Calculate molar volume for a sample of the molar mass of the N 2 if the density of the gas is 1.250 g/L? Solution:
Use the ideal gas equation to calculate the moles of gas. Push the plunger in until the volume is 20 mL and record the pressure and volume in your Excel file to the proper number of digits. Repeat the readings at 15 mL, 40 mL, 50 mL and 60 mL. Graphs: 1. Open your template graph file, draw a graph of P vs V, fit the curve and copy the graph to ... The volume of a gas is 500 ml at 760 mmHg. If the pressure is reduced to 380 mmHg and the temperature is constant, what will be the new volume? ... At constant temperature, the product of pressure and volume is constant (Boyle's law). Use that to find the new volume. P 1 V 1 = P 2 V 2 .Flowmeters, and sensors are used to measure the volumetric or mass flow rate of a liquid or a gas. We have the appropriate flow instruments for your flow measurement needs. Choose from a variety of variable area flow meters (rotameters) and electrical flow meters including gas mass, differential pressure, turbine, paddle-wheel sensors, gear ...
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